<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-35396532</id><updated>2011-04-21T20:36:13.278-03:00</updated><title type='text'>Geometría con Cabri</title><subtitle type='html'>Construcciones geométricas, propiedades de las figuras y deducciones de fórmulas.</subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://geomcabri.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://geomcabri.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Rodolfo</name><uri>http://www.blogger.com/profile/02019317896130788981</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>4</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-35396532.post-116585708755443290</id><published>2006-12-11T14:02:00.000-03:00</published><updated>2006-12-11T14:23:09.616-03:00</updated><title type='text'></title><content type='html'>¿Cómo construir un rombo que mantenga sus propiedades al mover alguno de sus vértices?&lt;br /&gt;Si conocen otros procedimientos por favor enviar información.&lt;br /&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/x/blogger/1020/3938/1600/514488/rombo1.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/x/blogger/1020/3938/400/865869/rombo1.jpg" border="0" /&gt;&lt;/a&gt;&lt;/p&gt;&lt;br /&gt;&lt;br /&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/x/blogger/1020/3938/1600/575957/rombo2.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/x/blogger/1020/3938/400/794938/rombo2.jpg" border="0" /&gt;&lt;/a&gt;&lt;/p&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/x/blogger/1020/3938/1600/118647/rombo3.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/x/blogger/1020/3938/400/123838/rombo3.jpg" border="0" /&gt;&lt;/a&gt;&lt;/p&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/x/blogger/1020/3938/1600/14457/rombo6.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/x/blogger/1020/3938/400/897923/rombo6.jpg" border="0" /&gt;&lt;/a&gt;&lt;/p&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/x/blogger/1020/3938/1600/502866/rombo5.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/x/blogger/1020/3938/400/243799/rombo5.jpg" border="0" /&gt;&lt;/a&gt;&lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/35396532-116585708755443290?l=geomcabri.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://geomcabri.blogspot.com/feeds/116585708755443290/comments/default' title='Comentarios de la entrada'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=35396532&amp;postID=116585708755443290' title='0 Comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/116585708755443290'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/116585708755443290'/><link rel='alternate' type='text/html' href='http://geomcabri.blogspot.com/2006/12/cmo-construir-un-rombo-que-mantenga.html' title=''/><author><name>Rodolfo</name><uri>http://www.blogger.com/profile/02019317896130788981</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-35396532.post-116220893119261289</id><published>2006-10-30T08:36:00.000-03:00</published><updated>2006-10-30T09:14:36.570-03:00</updated><title type='text'></title><content type='html'>&lt;strong&gt;Deducción del área del triángulo con Cabri&lt;br /&gt;&lt;/strong&gt;1) Construir un rectángulo y en su interior un triángulo cuya base sea igual a la base del rectángulo y el vértice opuesto forme parte del lado del rectángulo como se observa en la siguiente figura:&lt;br /&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Tri.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1020/3938/320/Tri.jpg" border="0" /&gt;&lt;/a&gt;&lt;/p&gt;&lt;p align="left"&gt;2) Calcular el área de ambas figuras y comparar los resultados.&lt;/p&gt;&lt;p align="left"&gt;3) Mover el vértice del triángulo como se indica en la siguiente figura y comparar las áreas.&lt;/p&gt;&lt;p align="left"&gt;&lt;/p&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Tri.png"&gt;&lt;/a&gt;&lt;/p&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Dibujo.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1020/3938/320/Dibujo.jpg" border="0" /&gt;&lt;/a&gt;&lt;/p&gt;&lt;p align="left"&gt;Se observa que el área del triángulo siempre es la mitad del área del rectángulo por lo tanto:&lt;/p&gt;&lt;p align="center"&gt;&lt;span style="color:#ff0000;"&gt;&lt;strong&gt;ÁREA DEL TRIÁNGULO = base x altura /2&lt;/strong&gt;&lt;/span&gt;&lt;/p&gt;&lt;p align="center"&gt;&lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Dibujo.jpg"&gt;&lt;/a&gt; &lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/35396532-116220893119261289?l=geomcabri.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://geomcabri.blogspot.com/feeds/116220893119261289/comments/default' title='Comentarios de la entrada'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=35396532&amp;postID=116220893119261289' title='1 Comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/116220893119261289'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/116220893119261289'/><link rel='alternate' type='text/html' href='http://geomcabri.blogspot.com/2006/10/deduccin-del-rea-del-tringulo-con.html' title=''/><author><name>Rodolfo</name><uri>http://www.blogger.com/profile/02019317896130788981</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>1</thr:total></entry><entry><id>tag:blogger.com,1999:blog-35396532.post-116075024071370826</id><published>2006-10-13T11:30:00.000-03:00</published><updated>2006-10-13T11:37:20.720-03:00</updated><title type='text'></title><content type='html'>Procedimiento para la construcción del rectángulo usando el programa de geometría Cabri. &lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Dibujo%201.0.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1020/3938/400/Dibujo%201.0.jpg" border="0" /&gt;&lt;/a&gt;&lt;br /&gt;&lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Dibujo%202.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1020/3938/400/Dibujo%202.jpg" border="0" /&gt;&lt;/a&gt; &lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Dibujo%203.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1020/3938/400/Dibujo%203.jpg" border="0" /&gt;&lt;/a&gt; &lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/Dibujo%204.jpg"&gt;&lt;img style="CURSOR: hand" alt="" src="http://photos1.blogger.com/blogger/1020/3938/400/Dibujo%204.jpg" border="0" /&gt;&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/35396532-116075024071370826?l=geomcabri.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://geomcabri.blogspot.com/feeds/116075024071370826/comments/default' title='Comentarios de la entrada'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=35396532&amp;postID=116075024071370826' title='2 Comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/116075024071370826'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/116075024071370826'/><link rel='alternate' type='text/html' href='http://geomcabri.blogspot.com/2006/10/procedimiento-para-la-construccin-del.html' title=''/><author><name>Rodolfo</name><uri>http://www.blogger.com/profile/02019317896130788981</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>2</thr:total></entry><entry><id>tag:blogger.com,1999:blog-35396532.post-115981034274163583</id><published>2006-10-02T14:18:00.000-03:00</published><updated>2006-10-09T14:30:43.430-03:00</updated><title type='text'></title><content type='html'>&lt;span style="color:#cc0000;"&gt;&lt;strong&gt;¿Cómo construir un rectángulo con Cabri?&lt;/strong&gt;&lt;/span&gt;&lt;br /&gt;Si bien el rectángulo se puede construir a simple vista con la herramienta polígono no es seguro que la figura cumpla con las propidedades del rectángulo, además si movemos uno de sus vértices la figura deja de ser un rectángulo.&lt;br /&gt;Si conocen algún procedimiento que permita construir un rectángulo que mantenga las propiedades al mover un vértice, envíen sus comentarios.&lt;br /&gt;Próximamente se publicarán los posibles procedimientos de construcción en este sitio.&lt;br /&gt;Saludos&lt;br /&gt;Rodolfo&lt;br /&gt;&lt;a href="http://photos1.blogger.com/blogger/1020/3938/1600/rectangulo.1.jpg"&gt;&lt;/a&gt;&lt;br /&gt;&lt;p align="left"&gt;&lt;/p&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/35396532-115981034274163583?l=geomcabri.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://geomcabri.blogspot.com/feeds/115981034274163583/comments/default' title='Comentarios de la entrada'/><link rel='replies' type='text/html' href='http://www.blogger.com/comment.g?blogID=35396532&amp;postID=115981034274163583' title='3 Comentarios'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/115981034274163583'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/35396532/posts/default/115981034274163583'/><link rel='alternate' type='text/html' href='http://geomcabri.blogspot.com/2006/10/cmo-construir-un-rectngulo-con-cabri.html' title=''/><author><name>Rodolfo</name><uri>http://www.blogger.com/profile/02019317896130788981</uri><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>3</thr:total></entry></feed>
